## Liars, truth-tellers, mathematicians and physicists

Posted on: March 10th, 2014 by
6

There are N mathematicians and N physicists in a circular table. Some of them are liars and some are truth-tellers. The number of truth tellers who are mathematicians is equal to the number of truth teller a who are physicists. They are all asked, "Is the person next to you a mathematician or a physicist?" They all reply "physicist." Show that N must be even.

- via AMS math society

#### 6 Responses to Liars, truth-tellers, mathematicians and physicists

They could be sitting in an alternating arrangement, with all mathematicians telling the truth and all physicists lying. This works for any N (odd or even).

it is mentioned that the number of truth tellers that are mathematicians equals the number of truth tellers who are physicists. In your scenario, they are not.

Ah, looks like the wording was just clarified.

Sorry for the error.

If n = 1 and Math (as always) tells the ruth and Physicist lies then they all will respond "Physicist".
This appears to satisfy the conditions of the problem Yet n IS NOT even. How do YOU show that N is even?